That would be 8/(2x(2+2)) if we were keeping it all in the denominator. Multiplication happens in the numerator if there are no parenthesis to distinguish it. If thr equation was written like this:
8
2x(2+2)
Then you would also be correct, but I have to respectfully disagree with your analysis.
There isn’t a multiplication symbol though. By your logic something like 8÷2x would mean (8÷2)*x because order of operations
Or if you read 8÷2√x as (8÷2)*√x
Just notate 8÷2(2+2) as 8÷2x; x=(2+2) and you get it, you can substitute any complete expression with a variable in an equation and the logic stays the same.
… the one on the right is correct… that’s a jank ass calculator on the left that doesn’t know how to do order of operations 8/2×(2+2) 8/2x4 4x4 16
No, it isn’t.
…isn’t the same thing as 8/2(2+2). You separated the term in the denominator, leading the (2+2) to get flipped into the numerator, hence wrong answer.
That would be 8/(2x(2+2)) if we were keeping it all in the denominator. Multiplication happens in the numerator if there are no parenthesis to distinguish it. If thr equation was written like this:
8
2x(2+2)
Then you would also be correct, but I have to respectfully disagree with your analysis.
(2x(2+2)) is the same thing as 2(2+2)
Which means you disagree with how Maths textbooks teach how to do this (see previous link).
There isn’t a multiplication symbol though. By your logic something like
8÷2xwould mean(8÷2)*xbecause order of operationsOr if you read
8÷2√xas(8÷2)*√xJust notate
8÷2(2+2)as8÷2x; x=(2+2)and you get it, you can substitute any complete expression with a variable in an equation and the logic stays the same.You know sometimes both are correct.
Nope. That’s what the order of operations rules take care of.