If (Box A Taken = True)
{place ($0) inBox B}
else
{place ($1,000,000,000) inBox B}
Machine doesnt care if you also take Box B, it only cares if Box A is one of the boxes taken. If you take no boxes, Box B would still have a billion dollars, although thats kinda dumb choice from a gameshow host’s perspective.
Does the machine know that box is not an option? Thinking that A, A+B, and B are all valid options is something I could see an AI doing.
There also isn’t much penalty for taking A+B? You’ll always get at least $1M. And if you took only B, the max you could get is $1M.
Edit: I can’t read lol. I’d still take both, the result is Predicted A+B: $1M Predicted B only: $1001M
If you only take box B, the result is Predicted A+B: $0 Predicted B only: $1000M
I think the machine predicts 2 results, either
Box A is taken = True
OR
Box A is taken = False
Something like:
If (Box A Taken = True) {place ($0) in Box B} else {place ($1,000,000,000) in Box B}
Machine doesnt care if you also take Box B, it only cares if Box A is one of the boxes taken. If you take no boxes, Box B would still have a billion dollars, although thats kinda dumb choice from a gameshow host’s perspective.